Problem: A 25.0 mL sample of 0.125 M pyridine, C5H5N, is titrated with 0.100 M HCl. The Kb of C5H5N is 1.7 x 10-9.Calculate the pH at one-half equivalence point.

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We are given being asked to determine the pH of a 25.0-mL sample of 0.125 M pyridine titrated with 0.100 M HCl at one-half equivalence point.



Pyridine is a weak base and HCl is a strong acid. So, this is a weak base-strong acid titration


At one-half equivalence point,

[weak base] = [conjugate base]


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Problem Details

A 25.0 mL sample of 0.125 M pyridine, C5H5N, is titrated with 0.100 M HCl. The Kb of C5H5N is 1.7 x 10-9.

Calculate the pH at one-half equivalence point.

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