We’re being asked to determine the number of σ and π bonds in (CH3)2CCHCH2CCCOOH. For this, we first need to draw the Lewis structure of (CH3)2CCHCH2CCCOOH. The steps in drawing Lewis structures are as follows:
• Hydrogen cannot be the central atom and oxygen prefers to make 2 bonds which mean carbon is the central atom.
• The first two carbons will be attached to the third carbon and the other carbons will be bonded with each other. We will write them in order as they are written. We will also attached the two oxygens in the last carbon.
Then we’ll add hydrogens to each carbon based on the formula (1st 2 carbons get 3 H, 3rd carbon gets none, 4th carbon gets 1 H, 5th carbon gets 2 H, 6th-8th carbons get none, and 1 O gets 1 H):
How many sigma bonds and pi bonds does this molecule have?
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Valence Shell Electron Pair Repulsion Theory concept. You can view video lessons to learn Valence Shell Electron Pair Repulsion Theory. Or if you need more Valence Shell Electron Pair Repulsion Theory practice, you can also practice Valence Shell Electron Pair Repulsion Theory practice problems.