Problem: Calculate the pH of the resulting solution if 35.0 mL of 0.350 M HCl(aq) is added to 25.0 mL of 0.450 M NaOH(aq)

FREE Expert Solution

Determine the moles of OH-and H+ from 25 mL of 0.450 M NaOH and 35 mL of 0.350 M HCl then figure out the excess Hor OH- to calculate for the pH

  • HCl is one of the common strong acids where it produces 1 mole of H+ or H3O+

HCl (aq) → H+ (aq) + Cl- (aq)

  • On the other hand, NaOH is a strong base since OH- is ionically bond to a Group 1A metal where 1 mole of NaOH produces 1 mole of OH-:

NaOH (aq) → Na+ (aq) + OH-(aq)

  • Recall that molarity is calculated as:

Molarity = moles of soluteL of solution

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Problem Details

Calculate the pH of the resulting solution if 35.0 mL of 0.350 M HCl(aq) is added to 25.0 mL of 0.450 M NaOH(aq)

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