# Problem: The reactant concentration in a second-order reaction was 0.510 M after 205 s and 5.10×10−2 M after 805 s. What is the rate constant for this reaction?The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line

###### FREE Expert Solution

The integrated rate law for a second-order reaction is as follows:

$\overline{)\frac{\mathbf{1}}{{\mathbf{\left[}\mathbf{A}\mathbf{\right]}}_{\mathbf{t}}}{\mathbf{=}}{\mathbf{kt}}{\mathbf{+}}\frac{\mathbf{1}}{{\mathbf{\left[}\mathbf{A}\mathbf{\right]}}_{\mathbf{0}}}}$

where:

[A]t = concentration at time t

k = rate constant

t = time

[A]0 = initial concentration

91% (322 ratings) ###### Problem Details

The reactant concentration in a second-order reaction was 0.510 M after 205 s and 5.10×10−2 M after 805 s. What is the rate constant for this reaction?

The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line