Problem: The reactant concentration in a second-order reaction was 0.510 M after 205 s and 5.10×10−2 M after 805 s. What is the rate constant for this reaction?The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line

FREE Expert Solution

The integrated rate law for a second-order reaction is as follows:


1[A]t=kt+1[A]0


where: 

[A]t = concentration at time t

k = rate constant

t = time

[A]0 = initial concentration


91% (322 ratings)
View Complete Written Solution
Problem Details

The reactant concentration in a second-order reaction was 0.510 M after 205 s and 5.10×10−2 M after 805 s. What is the rate constant for this reaction?

The integrated rate laws for zero-, first-, and second-order reaction may be arranged such that they resemble the equation for a straight line

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Integrated Rate Law concept. You can view video lessons to learn Integrated Rate Law. Or if you need more Integrated Rate Law practice, you can also practice Integrated Rate Law practice problems.