We are being asked to determine the volume (mL) of a 15% (m/v) NaOH solution that contains 120 g NaOH

Recall the formula for %(m/v)

$\overline{){\mathbf{\%}}\mathbf{\left(}\raisebox{1ex}{$\mathbf{m}$}\!\left/ \!\raisebox{-1ex}{$\mathbf{v}$}\right.\mathbf{\right)}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{mass}\mathbf{}\mathbf{solute}\mathbf{}\mathbf{\left(}\mathbf{g}\mathbf{\right)}}{\mathbf{volume}\mathbf{}\mathbf{solution}\mathbf{}\mathbf{\left(}\mathbf{mL}\mathbf{\right)}}{\mathbf{\times}}{\mathbf{100}}}$

14) What volume (mL) of a 15% (m/v) NaOH solution contains 120 g NaOH?

A) 18 ml B) 0.13 mL C) 13 mL D) 120 mL E) 8.0 x 10^{2} mL

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