Formic acid is weak so we have to use an ICE chart to solve.
We’re being asked to calculate the pH of a 0.240 M aqueous solution of HCOOH.
HCOOH(aq) + H2O(l) ⇌ H3O+(aq) + HCOO–(aq); Ka = 1.8 × 10–4
From this, we can construct an ICE table. Remember that liquids are ignored in the ICE table.
Determine the [H3O+] of a 0.240M solution of formic acid.
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