# Problem: Barium chloride reacts with sodium sulfate according to the following equation: BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2 NaCl(aq). A student mixes a solution containing 10.0 g BaCl2 (M = 208.2) with a solution containing 10.0 g Na2SO4 (M = 142.1) and obtains 12.0 g BaSO4 (M = 233.2). What is the percent yield of this reaction?

###### FREE Expert Solution

We’re given the following balanced reaction:

BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2 NaCl(aq)

Step 1: Calculate the mass of BaSO4 that will be formed in the reaction of 10.0 g BaCl2 and 10.0 g Na2SO4.

Notice that we are given the mass of both reactants: this means we need to determine the limiting reactant, which is the reactant that forms the less amount of product

This is because once the limiting reactant is all used up, the reaction can no longer proceed and make more products.

This means the limiting reactant determines the maximum mass of the product formed.

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###### Problem Details

Barium chloride reacts with sodium sulfate according to the following equation: BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2 NaCl(aq). A student mixes a solution containing 10.0 g BaCl2 (M = 208.2) with a solution containing 10.0 g Na2SO4 (M = 142.1) and obtains 12.0 g BaSO4 (M = 233.2). What is the percent yield of this reaction?