Part C. Calculate the energy (in joules) of each photon that is emitted from a patch of ground that is at 27°C. Use the value of λmax of that temperature as your wavelength. Note that you must drag the arrow to the right of the thermometer to adjust temperature values in the simulation, which are shown in units of kelvins (K) above the thermometer.
Visible light is a type of electromagnetic (EM) radiation. EM radiation has wavelike characteristics, which are periodic oscillations with a fixed distance between peaks (wavelength, λ) and a consistent number of cycles per second (frequency, ν). The interactions between matter and light are quantized in nature, which means specific packets, rather than a continuous gradient, of EM radiation are absorbed and emitted by atoms. The relationship between frequency (ν, Greek nu) and wavelength (λ, Greek lambda) can be described by the following equation:
c = λν
where c is the speed of light. The speed of light is a constant that is specified for each medium, and it has the value of 2.998 × 108 m/s in vacuum. Therefore, the frequency of light can be determined if the wavelength is known and vice versa.
The phenomenon known as blackbody radiation is the temperature-dependent emission of EM radiation. At any given temperature, a broad range of wavelengths is being emitted by materials, and the wavelength at which the emission intensity of EM radiation is highest is denoted as λmax. Both λmax and the range of wavelengths shift with temperature, as can be observed in the simulation
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