Problem: Calculate the mass of glucose metabolized by an 89.5 kg person in climbing a mountain with an elevation gain of 1350 m. Assume that the work performed in the climb is four times that required to simply lift 89.5 kg by 1350 m.The metabolism of glucose, C6H12O6, yields carbon dioxide, CO2(g), and water, H2O(l), as products. Energy released in this metabolic process is converted to useful work, w, with about 66.0% efficiency. The formula for work isw = mdgwhere m is mass, d is distance, and g = 9.81 m ⋅ s−2 is the acceleration due to gravity.Use the data below to answer questions about the metabolism of glucose.

FREE Expert Solution
98% (261 ratings)
Problem Details

Calculate the mass of glucose metabolized by an 89.5 kg person in climbing a mountain with an elevation gain of 1350 m. Assume that the work performed in the climb is four times that required to simply lift 89.5 kg by 1350 m.

The metabolism of glucose, C6H12O6, yields carbon dioxide, CO2(g), and water, H2O(l), as products. Energy released in this metabolic process is converted to useful work, w, with about 66.0% efficiency. The formula for work is

w = mdg

where m is mass, d is distance, and g = 9.81 m ⋅ s−2 is the acceleration due to gravity.

Use the data below to answer questions about the metabolism of glucose.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Enthalpy of Formation concept. You can view video lessons to learn Enthalpy of Formation. Or if you need more Enthalpy of Formation practice, you can also practice Enthalpy of Formation practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Xidos' class at University of Manitoba.