# Problem: A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 16.7 mL of 1.50 M H2SO4 was needed? The equation is2 KOH(aq) + H2SO4(aq) → K2SO4(aq) + 2 H2O(l)Express your answer with the appropriate units.A titration is a procedure for determining the concentration of a solution by allowing it to react with another solution of known concentration (called a standard solution). Acid-base reactions and oxidation-reduction reactions are used in titrations. For example, to find the concentration of an HCl solution (an acid), a standard solution of NaOH (a base) is added to a measured volume of HCl from a calibrated tube called a buret. An indicator is also present and it will change color when all the acid has reacted. Using the concentration of the standard solution and the volume dispensed, we can calculate molarity of the HCl solution.

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A volume of 90.0 mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 16.7 mL of 1.50 M H2SOwas needed? The equation is

2 KOH(aq) + H2SO4(aq) → K2SO4(aq) + 2 H2O(l)