Problem: What mass of melamine, C3N3(NH2)3, will be obtained from 194.0 kg of urea, CO(NH2)2, if the yield of the overall reaction is 77.0 % ?Melamine, C3N3(NH2)3, is used in adhesives and resins. It is manufactured in a two-step process in which urea, CO(NH2)2, is the sole starting material, isocyanic acid, HNCO, is an intermediate, and ammonia, NH3, and carbon dioxide, CO2, gases are byproducts.In the first step of this reaction, urea is broken down into isocyanic acid and ammonia:CO(NH2)2(l) → HNCO(l) + NH3(g)

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What mass of melamine, C3N3(NH2)3, will be obtained from 194.0 kg of urea, CO(NH2)2, if the yield of the overall reaction is 77.0 % ?

Melamine, C3N3(NH2)3, is used in adhesives and resins. It is manufactured in a two-step process in which urea, CO(NH2)2, is the sole starting material, isocyanic acid, HNCO, is an intermediate, and ammonia, NH3, and carbon dioxide, CO2, gases are byproducts.
In the first step of this reaction, urea is broken down into isocyanic acid and ammonia:
CO(NH2)2(l) → HNCO(l) + NH3(g)

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