Problem: Part A. The conversion factor relating miles to meters is 1 mile = 1610 m.The speed of light is 3.00 × 108 m/ s. How fast is this in miles per hour (miles/ h)?Keeping track of units during conversions can get confusing. Therefore, a good strategy is to use dimensional analysis. In dimensional analysis, conversion factors are used to cancel out unwanted units and leave the desired units.Consider the following example: How many football fields could fit on a 1 mile stretch of land? Here are the relevant conversion factors:1 football field = 100 yards1 mile = 5280 ft1 yard = 3 ftThen1 mile×5280 ft1 mil3×1 yard3 ft×1 football field100 yard=17.6 football fields

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Problem Details

Part A. The conversion factor relating miles to meters is 1 mile = 1610 m.

The speed of light is 3.00 × 108 m/ s. How fast is this in miles per hour (miles/ h)?


Keeping track of units during conversions can get confusing. Therefore, a good strategy is to use dimensional analysis. In dimensional analysis, conversion factors are used to cancel out unwanted units and leave the desired units.

Consider the following example: How many football fields could fit on a 1 mile stretch of land? Here are the relevant conversion factors:

1 football field = 100 yards
1 mile = 5280 ft
1 yard = 3 ft

Then

1 mile×5280 ft1 mil3×1 yard3 ft×1 football field100 yard=17.6 football fields


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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Dimensional Analysis concept. You can view video lessons to learn Dimensional Analysis. Or if you need more Dimensional Analysis practice, you can also practice Dimensional Analysis practice problems.