ΔH = -555 kJ/1 mol CH3OH
The complete combustion of ethanol, C2H5OH (FW = 46.0 g/mol), proceeds as follows:
C2H5OH(l) + 3 O2 (g) → 2 CO2 (g) + 3 H2O(l) ΔH = − 555 kJ
What is the enthalpy change for combustion of 15.0 g of ethanol?
a) -12.1 kJ
b) -181 kJ
c) -422 kJ
d) -555 kJ
e) -1700 kJ
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