Recall that work (w) is given by:

$\overline{){\mathbf{w}}{\mathbf{=}}{\mathbf{-}}{\mathbf{P\Delta V}}}$

where:

P = pressure (in atm)

ΔV = V_{final} – V_{initial} = change in volume (in L)

Also note that if work is:

• (+): work is done by the surroundings to the system (compression)

• (–): work is done by the system to the surroundings (expansion)

If a balloon is expanded from 0.055 L to 1.403 L against an external pressure of 1.02 atm, how many L⋅atm of work is done?

a) 0.056 L⋅atm

b) -1.37 L⋅atm

c) 1.43 L⋅atm

d) 1.49 L⋅atm

e) 1.39 L⋅atm

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