# Problem:  Describe how you would prepare 350.0 mL of 0.100 M C12H22O11 starting with 3.00 L of 1.50 M C12H22O11.

###### FREE Expert Solution

$\overline{){{\mathbf{M}}}_{{\mathbf{1}}}{{\mathbf{V}}}_{{\mathbf{1}}}{\mathbf{=}}{{\mathbf{M}}}_{{\mathbf{2}}}{{\mathbf{V}}}_{{\mathbf{2}}}}$

M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume

M1 = 1.50 M C12H22O11
V1 = ?
M2 = 0.100 M C12H22O11
V2 = 350.0 mL

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###### Problem Details

Describe how you would prepare 350.0 mL of 0.100 M C12H22O11 starting with 3.00 L of 1.50 M C12H22O11.

What scientific concept do you need to know in order to solve this problem?

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What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Lau's class at NEWARK.