Problem: A 3.045 g sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of the sample. The resultant reaction produced a precipitate of barium sulfate, which was collected by filtration, washed, dried, and weighed.If 0.3080 g of barium sulfate was obtained, what was the mass percentage of barium in the sample?

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% mass = mass bariummass sample×100


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A 3.045 g sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of the sample. The resultant reaction produced a precipitate of barium sulfate, which was collected by filtration, washed, dried, and weighed.

If 0.3080 g of barium sulfate was obtained, what was the mass percentage of barium in the sample?

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