# Problem: When 24 mol of methanol and 15 mol of oxygen combine in the combustion reaction, 2 CH3OH(g) + 3 O2 (g) → 2 CO2 (g) + 4 H2O(g) what is the excess reactant and how many moles of it remain at the end of the reaction?a) 9 mol CH3OH (g)b) 10 mol CO2  (g) c) 10 mol CH3OH (g)d) 14 mol CH3OH (g)e) 1 mol O2 (g)

###### FREE Expert Solution

Step 1

= 24 mol CO2

= 10 mol CO2

84% (165 ratings) ###### Problem Details

When 24 mol of methanol and 15 mol of oxygen combine in the combustion reaction,

2 CH3OH(g) + 3 O2 (g) → 2 CO2 (g) + 4 H2O(g)

what is the excess reactant and how many moles of it remain at the end of the reaction?

a) 9 mol CH3OH (g)

b) 10 mol CO2  (g)

c) 10 mol CH3OH (g)

d) 14 mol CH3OH (g)

e) 1 mol O2 (g)

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