We are asked how many Ge atoms contain a 9 nm quantum dot of germanium.

Calculate volume:

$\mathbf{V}\mathbf{}\mathbf{=}\frac{\mathbf{1}}{\mathbf{6}}{\mathbf{\pi d}}^{\mathbf{3}}\phantom{\rule{0ex}{0ex}}\mathbf{V}\mathbf{}\mathbf{=}\frac{\mathbf{1}}{\mathbf{6}}\mathbf{\pi}{(9\mathrm{nm})}^{\mathbf{3}}$

**V = 381.7 nm**^{3}

Very small crystals composed of 1000 to 100,000 atoms, called quantum dots, are being investigated for use in electronic devices.. (c) The density of germanium is 5.325 g/cm^{3} . If you made a 9 nm quantum dot of germanium, how many Ge atoms would it contain? Assume the dot is spherical. Express your answer using four significant figures.

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