# Problem: Evaporating sweat cools the body because evaporation is an endothermic process:H2O(l) → H2O(g)                 ΔH°rxn = +44.01kJEstimate the mass of water that must evaporate from the skin to cool the body by 0.45°C. Assume a body mass of 100 kg and assume that the specific heat capacity of the body is 4.0 J/g⋅°C.

###### FREE Expert Solution
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###### FREE Expert Solution

Recall that heat can be calculated using the following equation:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{mc}}{\mathbf{∆}}{\mathbf{T}}}$

q = heat, J

+qabsorbs heat
–qloses heat

m = mass (g)
c = specific heat capacity = J/(g·°C)
ΔT = Tf – Ti = (°C)

Based on the given system:

92% (248 ratings)
###### Problem Details

Evaporating sweat cools the body because evaporation is an endothermic process:
H2O(l) → H2O(g)                 ΔH°rxn = +44.01kJ

Estimate the mass of water that must evaporate from the skin to cool the body by 0.45°C. Assume a body mass of 100 kg and assume that the specific heat capacity of the body is 4.0 J/g⋅°C.