Recall that heat can be calculated using the following equation:
q = heat, J
• +q → absorbs heat
• –q → loses heat
m = mass (g)
c = specific heat capacity = J/(g·°C)
ΔT = Tf – Ti = (°C)
Based on the given system:
Evaporating sweat cools the body because evaporation is an endothermic process:
H2O(l) → H2O(g) ΔH°rxn = +44.01kJ
Estimate the mass of water that must evaporate from the skin to cool the body by 0.45°C. Assume a body mass of 100 kg and assume that the specific heat capacity of the body is 4.0 J/g⋅°C.
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