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**Problem**: Evaporating sweat cools the body because evaporation is an endothermic process:H2O(l) → H2O(g) ΔH°rxn = +44.01kJEstimate the mass of water that must evaporate from the skin to cool the body by 0.45°C. Assume a body mass of 100 kg and assume that the specific heat capacity of the body is 4.0 J/g⋅°C.

###### FREE Expert Solution

###### FREE Expert Solution

Recall that heat can be calculated using the following equation:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{mc}}{\mathbf{\u2206}}{\mathbf{T}}}$

q = heat, J

• **+q** → **absorbs **heat

• **–q** → **l****oses **heat

m = mass (g)

c = specific heat capacity = J/(g·°C)

ΔT = T_{f} – T_{i} = (°C)

**Based on the given system:**

###### Problem Details

Evaporating sweat cools the body because evaporation is an endothermic process:

H_{2}O(l) → H_{2}O(g) ΔH°rxn = +44.01kJ

Estimate the mass of water that must evaporate from the skin to cool the body by 0.45°C. Assume a body mass of 100 kg and assume that the specific heat capacity of the body is 4.0 J/g⋅°C.

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