Recall that heat can be calculated using the following equation:

$\overline{){\mathbf{q}}{\mathbf{=}}{\mathbf{mc}}{\mathbf{\u2206}}{\mathbf{T}}}$

q = heat, J

• **+q** → **absorbs **heat

• **–q** → **l****oses **heat

m = mass (g)

c = specific heat capacity = J/(g·°C)

ΔT = T_{f} – T_{i} = (°C)

**Based on the given system:**

Evaporating sweat cools the body because evaporation is an endothermic process:

H_{2}O(l) → H_{2}O(g) ΔH°rxn = +44.01kJ

Estimate the mass of water that must evaporate from the skin to cool the body by 0.45°C. Assume a body mass of 100 kg and assume that the specific heat capacity of the body is 4.0 J/g⋅°C.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Calorimetry concept. You can view video lessons to learn Calorimetry. Or if you need more Calorimetry practice, you can also practice Calorimetry practice problems.