Step 1: Calculate the initial amount (in moles) of the HNO3 and Ca(OH)2
moles HNO3 = 0.0125 mol HNO3
moles Ca(OH)2 = 0.006 mol Ca(OH)2
The amount of HNO3 is greater than Ca(OH)2, therefore there will be HNO3 left after the reaction
Step 2: Calculate the amount of HNO3 reacted
Balanced reaction: 2HNO3 + Ca(OH)2 → 2 H2O(l) + Ca(NO3)2(aq)
• 2 mole of HNO3 reacts with 1 mole of Ca(OH)2:
• mol of HNO3 reacted = mol Ca(OH)2 reacted÷2
moles HNO3 reacted = 0.0023 mol HNO3
Step 3: Calculate the amount of HNO3 left after the reaction
moles HNO3 left = moles HNO3 (initial) – moles HNO3 (reacted)
moles HNO3 left = 0.0125 mol HNO3 - 0.003 mol HNO3
moles HNO3 left = 0.0095 mol HNO3
Step 4: Calculate the concentration of HNO3 left in the solution
Final Volume of solution = 0.205 L
molarity = 0.0463 M HNO3
If the following solutions are mixed, is the resulting solution acidic, basic, or neutral?
125.0 mL of 0.100 M HNO3 and 80.0 mL of 0.0750 M Ca(OH)2
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