Recall that when becoming an ion, the element tries to achieve the configuration of the nearest noble gas.
Na (metal) + F (nonmetal) → ionic compound
For Na: The nearest noble gas is Ne and we can see that Na has 1 more electron than Ne. This means it needs to lose 1 electron to achieve a noble gas configuration and in doing so becomes Na+.
Na → Group 1A → 1 valence electrons
Na+ → will lose the 1 valence electron
For F: The nearest noble gas is Ne and we can see that I has 1 less electron than Ne. It needs to gain 1 electron to become F–.
F → Group 7A → 7 valence electrons
F– → will gain 1 electron → total of 8 electrons (represented by dots and enclosed in bracket)
The correct placement of electrons for NaF is:
Which of the following correctly represent the placement of electrons around each atom? Drag each item to the appropriate Bin.
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