Problem: Which atom has a change in oxidation number of +4 in the following redox reaction?K2Cr2O7 + H2O + S → KOH + Cr2O3 + SO2A) KB) CrC) OD) S

FREE Expert Solution

K2Cr2O7 + H2O + S → KOH + Cr2O3 + SO2

reactant

K2Cr2O7 

OS K = +1

OS O = -2


2(+1) + 2(OS Cr) + 7(-2) = 0

OS Cr = +6


H2

OS H = +1

OS O = -2


S

OS S = 0


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Problem Details

Which atom has a change in oxidation number of +4 in the following redox reaction?

K2Cr2O7 + H2O + S → KOH + Cr2O3 + SO2

A) K

B) Cr

C) O

D) S

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Calculate Oxidation Number concept. If you need more Calculate Oxidation Number practice, you can also practice Calculate Oxidation Number practice problems.