Problem: Separate this redox reaction into its component half-reactions.3 O2 + 4Cr →  2Cr2O3

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3 O2 + 4 Cr →  2 Cr2O3

2 Cr2O3 → 4 Cr3+ + 6 O2-


3 O2 →  6 O2-

O2 → standard state → oxidation state = 0

O2- → oxidation state = -2

0 → -2    gained 2 e- per O atom;

gain electron → reduction

3 O2 + 12 e- →  6 O2- 

O2 + 4 e- →  2 O2- 

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Problem Details

Separate this redox reaction into its component half-reactions.

3 O2 + 4Cr →  2Cr2O3

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