from NO_{2}

$\mathbf{4}\mathbf{.}\mathbf{5}\mathbf{}\overline{)\mathbf{mol}\mathbf{}{\mathbf{NO}}_{\mathbf{2}}}\mathbf{\times}\frac{\mathbf{2}\mathbf{}\mathbf{mol}\mathbf{}{\mathbf{HNO}}_{\mathbf{3}}}{\mathbf{3}\mathbf{}\overline{)\mathbf{mol}\mathbf{}{\mathbf{NO}}_{\mathbf{2}}}}$** = 3 mol HNO _{3}**

Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation:

3 NO_{2}(g) + H_{2}O(l) → 2 HNO_{3}(l) + NO(g)

Suppose that 4.5 mo NO_{2} and 0.40 mol H_{2}O combine and react completely. Which reactant is in excess?

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What scientific concept do you need to know in order to solve this problem?

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