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In this case, multiply, the enthalpy formation by 3 since -80.29 kJ/mol denotes 1 mole NH3
∆H of 3 mol NH3 = 3 mol NH3 (-80.29 kJ1 mol NH3)
The enthalpy for the formation of 1 mole of NH3(aq) is -80.29 kJ/mol. What is the ΔHf for the formation of 3 moles of NH3(aq)?
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