In this case, multiply, the enthalpy formation by 3 since -80.29 kJ/mol denotes 1 mole NH_{3}

$\mathbf{\u2206}\mathbf{H}\mathbf{}\mathbf{of}\mathbf{}\mathbf{3}\mathbf{}\mathbf{mol}\mathbf{}{\mathbf{NH}}_{\mathbf{3}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{3}\overline{)\mathbf{}\mathbf{mol}\mathbf{}{\mathbf{NH}}_{\mathbf{3}}}\mathbf{}\left(\frac{-80.29\mathrm{kJ}}{1\overline{)\mathrm{mol}\hspace{0.17em}{\mathrm{NH}}_{3}}}\right)$

The enthalpy for the formation of 1 mole of NH_{3}(aq) is -80.29 kJ/mol. What is the ΔHf for the formation of 3 moles of NH_{3}(aq)?

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