Problem: The pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl is?

FREE Expert Solution

KOH + HCl → KCl + H2O

strong   strong 

base       acid


Recall that moles = molarity × volume. 


Since:

  • molarity KOH = molarity HCl
  • volume KOH = volume HCl

Then:


MVacid=MVbase


This means:

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Problem Details

The pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl is?

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