Problem: Given that Kb for C6H5NH3+ is 1.7 x 10-9 at 25 °C, what is the value of Ka for C6H5NH3+ at 25 °C? Ka=____?

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Ka × Kb = KwKa =KwKb


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Given that Kb for C6H5NH3+ is 1.7 x 10-9 at 25 °C, what is the value of Ka for C6H5NH3+ at 25 °C? Ka=____?

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