**Calculate E****° _{cell}**

*$\overline{){\mathbf{E}}{{\mathbf{\xb0}}}_{{\mathbf{cell}}}{\mathbf{=}}{\mathbf{E}}{{\mathbf{\xb0}}}_{{\mathbf{cathode}}}{\mathbf{-}}{\mathbf{E}}{{\mathbf{\xb0}}}_{{\mathbf{anode}}}}$*

E°_{cell} = 0.988 V – 1.606 V

**E° _{cell} = -0.618**

**Calculate for the initial cell potential using the initial concentrations of the species using the Nernst Equation.**

**Given: **

E°cell = -0.618 V

n = 2 e^{-}

[N^{2+}] = 0.472 M

[M^{+}] = 0.929 M

The reaction involved:

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