Problem: What is the daughter nucleus produced when 188(Hg) undergoes positron emission?

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We are asked what is the daughter nucleus produced when 188(Hg) undergoes positron emission


Recall that in a nuclear reaction, the number of protons and neutrons are affected and the identity of the element changes. For Positron emission: forms a positron particle (01e, atomic mass = 0, atomic number = 1)


The incomplete nuclear equation is:

18880 Hg  ___ + 01e,


Atomic mass of the daughter nuclide:

188 = x + 0

x = 188 – 0188


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What is the daughter nucleus produced when 188(Hg) undergoes positron emission?