Problem: What is the daughter nucleus produced when 188(Hg) undergoes positron emission?
FREE Expert Solution
We are asked what is the daughter nucleus produced when 188(Hg) undergoes positron emission
Recall that in a nuclear reaction, the number of protons and neutrons are affected and the identity of the element changes. For Positron emission: forms a positron particle (01e, atomic mass = 0, atomic number = 1)
The incomplete nuclear equation is:
18880 Hg → ___ + 01e,
Atomic mass of the daughter nuclide:
188 = x + 0
x = 188 – 0 = 188
Problem Details
What is the daughter nucleus produced when 188(Hg) undergoes positron emission?
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