We are asked what is the daughter nucleus produced when 188(Hg) undergoes positron emission
Recall that in a nuclear reaction, the number of protons and neutrons are affected and the identity of the element changes. For Positron emission: forms a positron particle (01e, atomic mass = 0, atomic number = 1)
The incomplete nuclear equation is:
18880 Hg → ___ + 01e,
Atomic mass of the daughter nuclide:
188 = x + 0
x = 188 – 0 = 188
What is the daughter nucleus produced when 188(Hg) undergoes positron emission?