Problem: What pressure will 2.6 x 1023 molecules of H2 exert in a 3.9 L container at 45°C?A. 5.7 atmB. 1.7 atmC. 2.9 atmD. 3.4 atmE. 4.6 atm

FREE Expert Solution

Calculate moles of H2:

2.6×1023 molecule H2(1 mol H26.022×1023 molecule H2)=0.432 mol H2


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Problem Details

What pressure will 2.6 x 1023 molecules of H2 exert in a 3.9 L container at 45°C?

A. 5.7 atm

B. 1.7 atm

C. 2.9 atm

D. 3.4 atm

E. 4.6 atm