Sn (s) → Sn2+
Sn (s): O.S. = 0
Sn2+: O.S. = +2
change in OS: 0 to +2 → increase/lose electrons → oxidation → anode
Determine the cell notation for the redox reaction given below.
Sn(s) + 2 H+(aq) → Sn2+(aq) + H2(g)
a) H2(g) | H+(aq) | Pt ll Sn2+(aq) | Sn(s)
b) H+(aq) | H2(g) | Pt I| Sn(s)2+(aq)
c) Sn(s) | Sn2+(aq) || H+(aq) | H2(g) | Pt
d) Sn(s) | H2g || Sn2+(aq) I H+(aq) | Pt
e) Sn2+(aq) | Sn(s) || H2(g) | H+(aq) | Pt
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