(1) There is only O → no central atom
(2) Calculate the total number of valence electrons present.
Group Valence Electrons
O 6A 3 x 6 e‑ = 24 e‑
Total = 24 valence e-
(3): Draw the Lewis Structure for the molecule
• O → prefers to have complete octet (8 e- around them)
• O can have up to 2 bonds
Lewis structure of O3:
The electrons in the double bond can move from one O-O bond to another O-O bond while maintaining the formal charge of the central O and the overall charge equal to 0.
Keep in mind not to place more than 8 electrons around each O since it prefers to follow the octet rule.
Which of these molecules or ions exhibit resonance?
Drag each item to the appropriate bin.
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