(1) Calculate the pressure at 40°C using chemistry gas law. Recall that pressure and temperature are directly proportional

$\overline{)\frac{{\mathbf{P}}_{\mathbf{1}}}{{\mathbf{T}}_{\mathbf{1}}}{\mathbf{=}}\frac{{\mathbf{P}}_{\mathbf{2}}}{{\mathbf{T}}_{\mathbf{2}}}}\phantom{\rule{0ex}{0ex}}\frac{\mathbf{760}\mathbf{.}\mathbf{05}\mathbf{}\mathbf{mmHg}}{\mathbf{27}\mathbf{+}\mathbf{273}\mathbf{.}\mathbf{15}\mathbf{}\mathbf{K}}\mathbf{=}\frac{{\mathbf{P}}_{\mathbf{2}}}{\mathbf{40}\mathbf{+}\mathbf{273}\mathbf{.}\mathbf{15}\mathbf{}\mathbf{K}}$

P_{2} = 792.96 mmHg

You measure two different pressures of the sealed vial containing air and ethanol at two different temperatures; 890.27 mmHg at 27°C and 908.53 mmHg at 40°C. From earlier measurements you found that the pressure of air at 27°C is 760.05 mmHg. What is the vapor pressure?

At 27°C: 130.22 mmHg

At 40°C: _____ mmHg

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