Problem: At what temperature will He atoms have the same Crms value as N2 molecules at 25°C? Solve this problem without calculating the value of Crms for N2. Crms is the root mean square speed.

FREE Expert Solution

root mean square speed (C_rms):

$C_{rms} = \sqrt{\frac{3 RT}{M}}$

µ_rms = rms speed,
R = 8.314 J/(mol·K)
T = temperature, K
M = molar mass, kg/mol

• molar mass of N₂:

$M_{N_{2}} = 28.02 \frac{g}{mol} \times \frac{1 kg}{10^{3} g}$

M_N2 = 0.02802 kg/mol

• molar mass of He:

$M_{N_{2}} = 4.0026 \frac{g}{mol} \times \frac{1 kg}{10^{3} g}$

M_N2 = 4.0026x10^-3 kg/mol

C_rms N₂ = C_rms He

Problem Details

At what temperature will He atoms have the same C_rms value as N₂ molecules at 25°C? Solve this problem without calculating the value of C_rms for N₂. C_rms is the root mean square speed.

Learn this topic by watchingRoot Mean Square Speed Concept Videos

All Chemistry Practice Problems Root Mean Square Speed Practice Problems

See all problems in Root Mean Square Speed

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Root Mean Square Speed concept. You can view video lessons to learn Root Mean Square Speed. Or if you need more Root Mean Square Speed practice, you can also practice Root Mean Square Speed practice problems.

Problem: At what temperature will He atoms have the same Crms value as N2 molecules at 25°C? Solve this problem without calculating the value of Crms for N2. Crms is the root mean square speed.

FREE Expert Solution

Problem Details

Sign up for free to watch this video!