Redox Reactions Video Lessons

Video Thumbnail

Concept:

Problem: solveCl2(g) + 2LiBr(aq) → 2LiCl(aq) + Br2(l)a) Cl (in Cl2) is oxidized; Cl2 is the reducing agent. Br− (in LiBr) is reduced; LiBr is the oxidizing agent.b) Br− (in LiBr) is oxidized; LiBr is the oxidizing agent. Cl (in Cl2) is reduced; Cl2 is the reducing agent.c) Br− (in LiBr) is oxidized; LiBr is the reducing agent. Cl (in Cl2) is reduced; Cl2 is the oxidizing agent.d) Cl (in Cl2) is oxidized; Cl2 is the oxidizing agent. Br− (in LiBr) is reduced; LiBr is the reducing agent.

FREE Expert Solution

Cl2 (g)  elemental  O.S. = 0


LiBr

O.S. Li + O.S. Br = 0

(+1) + O.S. Br = 0

O.S. Br = -1


LiCl

O.S. Li + O.S. Cl = 0

(+1) + O.S. Cl = 0

O.S. Cl = -1


Br2 (g)  elemental  O.S. = 0


Change in O.S.

Li: +1 to +1 no change

Cl: 0 to -1  decrease/gain electrons  reduction  oxidizing agent

Br: -1 to 0 increase/lose electrons  oxidation reducing agent


80% (102 ratings)
View Complete Written Solution
Problem Details

solve

Cl2(g) + 2LiBr(aq) → 2LiCl(aq) + Br2(l)

a) Cl (in Cl2) is oxidized; Cl2 is the reducing agent. Br (in LiBr) is reduced; LiBr is the oxidizing agent.

b) Br (in LiBr) is oxidized; LiBr is the oxidizing agent. Cl (in Cl2) is reduced; Cl2 is the reducing agent.

c) Br− (in LiBr) is oxidized; LiBr is the reducing agent. Cl (in Cl2) is reduced; Cl2 is the oxidizing agent.

d) Cl (in Cl2) is oxidized; Cl2 is the oxidizing agent. Br (in LiBr) is reduced; LiBr is the reducing agent.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Redox Reactions concept. You can view video lessons to learn Redox Reactions. Or if you need more Redox Reactions practice, you can also practice Redox Reactions practice problems.