(1) Use the energy equation to find energy using frequency
E = (6.626x10-34 J•s) (4.68x1015 s-1)
E = 3.1x10-18 J
(2) Find work using the photoelectric effect
3.1x10-18 J = W + 5.70x10-19 J
When a metal was exposed to photons at a frequency of 4.68× 1015 s–1, electrons were emitted with a maximum kinetic energy of 5.70× 10–19 J.
Calculate the work function of this metal.
What is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 8.81× 10–7 J?
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