We are asked to which solution has the same number of moles of KCl as 75.00 mL of 0.250 M solution of KCl

Recall dilution equation:

$\overline{){\mathbf{mol}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{MV}}}$

Calculate mol for 75.00 mL of 0.250 M solution of KCl

$\mathbf{mol}\mathbf{}\mathbf{KCl}\mathbf{=}\mathbf{}\mathbf{MV}\phantom{\rule{0ex}{0ex}}\mathbf{mol}\mathbf{}\mathbf{KCl}\mathbf{=}(0.25\frac{\mathrm{mol}}{\overline{)L}})(75\overline{)\mathrm{mL}})\mathbf{\times}\frac{{\mathbf{10}}^{\mathbf{-}\mathbf{3}}\mathbf{}\mathbf{}\overline{)\mathbf{L}}}{\mathbf{1}\mathbf{}\overline{)\mathbf{mL}}\mathbf{}}\mathbf{}\mathbf{=}\mathbf{}\mathbf{0}\mathbf{.}\mathbf{0187}\mathbf{}\mathbf{mol}$

Calculate mole for each option:

Which solution has the same number of moles of KCl as 75.00 mL of 0.250 M solution of KCl?

A) 20.0 mL of 0.200 M solution of KCl

B) 25.0 mL of 0.175 M solution of KCl

C) 129 mL of 0.145 M solution of KCl

D) 50.0 mL of 0.125 M solution of KCl

E) 100 mL of 0.0500 M solution of KCl

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Molarity concept. You can view video lessons to learn Molarity. Or if you need more Molarity practice, you can also practice Molarity practice problems.

What professor is this problem relevant for?

Based on our data, we think this problem is relevant for Professor Dommer's class at UCSD.