**(1): Calculate the mass of the solute (NaCl).**

Assuming we have **100 g of solution**

**mass NaCl = 3.5 g**

**(2): MM of NaCl is 58.44 g/mol**

$\mathbf{mass}\mathbf{}\mathbf{NaCl}\mathbf{=}\mathbf{3}\mathbf{.}\mathbf{5}\mathbf{}\overline{)\mathbf{g}\mathbf{}\mathbf{NaCl}}\mathbf{\times}\frac{\mathbf{1}\mathbf{}\mathbf{mol}\mathbf{}\mathbf{NaCl}}{\mathbf{58}\mathbf{.}\mathbf{44}\mathbf{}\overline{)\mathbf{g}\mathbf{}\mathbf{NaCl}}}$

**moles NaCl = 0.0599 mol**

Assuming that seawater is a 3.50 mass % aqueous solution of NaCl, what is the molality of seawater?

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