Problem: Calculate the equilibrium constant, K, for the following reaction at 25 °C.Fe3+(aq) +   B(s) + 6H2O (l) -→  Fe(s) +   H3BO3(s) +   3H3O+(aq)The balanced reduction half-reactions for the above equation and their respective standard reduction potential values (E°) are as follows:Fe3+(aq)   +    3e-   →   Fe(s)                             E= -0.04 VH3BO3(s) +   3H3O+(aq) +   3e-   →   B(s) +   6H2O(l)      E= -.8698 VK = ?

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Calculate the equilibrium constant, K, for the following reaction at 25 °C.

Fe3+(aq) +   B(s) + 6H2O (l) -→  Fe(s) +   H3BO3(s) +   3H3O+(aq)


The balanced reduction half-reactions for the above equation and their respective standard reduction potential values (E°) are as follows:

Fe3+(aq)   +    3e-   →   Fe(s)                             E= -0.04 V

H3BO3(s) +   3H3O+(aq) +   3e-   →   B(s) +   6H2O(l)      E= -.8698 V

K = ?

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