Problem: The value of Ka for nitrous acid (HNO2) at 25 °C is 4.5×10−4.a. Write the chemical equation for the equilibrium that corresponds to Ka1. H+(aq) + NO−2(aq) ⇌ HNO2(aq)2. HNO2(aq) ⇌ H+(aq) + NO−2(aq)3. HNO2(aq) ⇌ H−(aq) + NO+2(aq)4. HNO2(aq) + H+(aq) ⇌ H2NO+2(aq)5. HNO2(aq) + H−(aq) ⇌ H2NO+2(aq)b. By using the value of Ka , calculate ΔG° for the dissociation of nitrous acid in aqueous solution.  c. What is the value of ΔG at equilibrium?        d. What is the value of ΔG when [H+] = 5.9  ×10−2 M , [NO−2] = 6.7 × 10−4 M , and [HNO2] = 0.21 M ?     

FREE Expert Solution

A.

Ka=productsreactants=[H+][NO2-][HNO2]

View Complete Written Solution
Problem Details

The value of Ka for nitrous acid (HNO2) at 25 °C is 4.5×10−4.

a. Write the chemical equation for the equilibrium that corresponds to Ka

1. H+(aq) + NO−2(aq) ⇌ HNO2(aq)

2. HNO2(aq) ⇌ H+(aq) + NO−2(aq)

3. HNO2(aq) ⇌ H(aq) + NO+2(aq)

4. HNO2(aq) + H+(aq) ⇌ H2NO+2(aq)

5. HNO2(aq) + H(aq) ⇌ H2NO+2(aq)

b. By using the value of Ka , calculate ΔG° for the dissociation of nitrous acid in aqueous solution.  

c. What is the value of ΔG at equilibrium?        

d. What is the value of ΔG when [H+] = 5.9  ×10−2 M , [NO−2] = 6.7 × 10−4 M , and [HNO2] = 0.21 M ?     

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Gibbs Free Energy concept. You can view video lessons to learn Gibbs Free Energy. Or if you need more Gibbs Free Energy practice, you can also practice Gibbs Free Energy practice problems.