The value of Ka for nitrous acid (HNO2) at 25 °C is 4.5×10−4.
a. Write the chemical equation for the equilibrium that corresponds to Ka
1. H+(aq) + NO−2(aq) ⇌ HNO2(aq)
2. HNO2(aq) ⇌ H+(aq) + NO−2(aq)
3. HNO2(aq) ⇌ H−(aq) + NO+2(aq)
4. HNO2(aq) + H+(aq) ⇌ H2NO+2(aq)
5. HNO2(aq) + H−(aq) ⇌ H2NO+2(aq)
b. By using the value of Ka , calculate ΔG° for the dissociation of nitrous acid in aqueous solution.
c. What is the value of ΔG at equilibrium?
d. What is the value of ΔG when [H+] = 5.9 ×10−2 M , [NO−2] = 6.7 × 10−4 M , and [HNO2] = 0.21 M ?
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