For acetate (CH3COO-)
(1) The total number of valence electrons present in CH3COO- is:
Group Valence Electrons
C 4A 2 × 4 e– = 8 e–
O 6A 2 × 6 e– = 12 e–
H 1A 3 × 1 e– = 3 e–
Total: 23 valence e–
Determine the shape around each central atom in the acetate ion. Draw the Lewis structure first.
(enter one of the following: linear, trigonal planar, tetrahedral, trigonal pyramidal, bent, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal, square planar)
A. _________ carbon 1
B. _________ carbon 2 (the one with the oxygens)
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