1.Cr3+ + e- →
Cr 2+ E°1= -0.407 V
Cr 2+ +2e- → Cr(s) E°2 = - 0.913
Given these standard reduction potentials at 25°C.
1.Cr3+ + e- → Cr2+ E°1= -0.407V
2.Cr2+ +2e- → Cr(s) E°2 = -0.913
Determine the standard reduction potential at 25°C for the following half-reaction equation.
Cr3+ + 3e- → Cr(s)
E°cell= ? V
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