Balancing Redox Reactions Video Lessons

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Problem: Balance the following equation in acidic conditions. Phases are optional. C2O42- + MnO2 → Mn2+ + CO2

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Balance the redox reaction under acidic conditions

C2O42- + MnO2 → Mn2+ + CO2

*Before balancing the redox reaction:

 ignore H+, OH-, and H2O in the starting reaction



Step 1: Separate the whole reaction into two half-reactions


C2O42- CO2                                                               MnO2 → Mn2+


Step 2: Balance the non-hydrogen and non-oxygen elements first


C2O42- → 2 CO2                                                               MnO2 → Mn2+

                                                                       (Mn: balanced)


Step 3: Balance oxygen by adding H2O(l) to the side that needs oxygen (1 O : 1 H2O)


C2O42- → 2 CO2                                                               MnO2 → Mn2+ + 2 H2O


Step 4: Balance hydrogen by adding H+ to the side that needs hydrogen (1 H: 1 H+)


C2O42- → 2 CO2                                                             4H+ +  MnO2 → Mn2+ + 2 H2O


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Problem Details

Balance the following equation in acidic conditions. Phases are optional. 

C2O42- + MnO2 → Mn2+ + CO2

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