MM CaCO_{3} = 100.09 g/mol

$\mathbf{mol}\mathbf{}\mathbf{O}\mathbf{\hspace{0.17em}}\mathbf{=}\mathbf{}\mathbf{25}\mathbf{.}\mathbf{45}\mathbf{}\overline{)\mathbf{g}}\mathbf{}\left(\frac{1\overline{)\mathrm{mol}{\mathrm{CaCO}}_{3}}}{100.09\overline{)g}}\right)\left(\frac{3\mathrm{mol}O}{1\overline{)\mathrm{mol}\hspace{0.17em}{\mathrm{CaCO}}_{3}}}\right)$

How many moles of oxygen are in 25.45 g of CaCO_{3}?

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