Problem: Calculate the pH of the resulting solution if 23.0 mL of 0.230 M HCl(aq) is added to(a) 33.0 mL of 0.230 M NaOH(aq).    (b) 13.0 mL of 0.330 M NaOH(aq).     

FREE Expert Solution

(1) Calculate moles of acid and base

mol H+ = 23 mL (1x10-3 L1 mL)(0.230 mol HCl1 L)(1 molH+1 mol HCl)

mol H+ = 0.00529

mol OH-= 33 mL (1x10-3 L1 mL)(0.230 mol NaOH1 L)(1 molOH-1 mol NaOH)

mol OH- = 0.00759


(2) Calculate excess base

0.00759 - 0.00529 = 0.0023 mol OH-

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Problem Details

Calculate the pH of the resulting solution if 23.0 mL of 0.230 M HCl(aq) is added to

(a) 33.0 mL of 0.230 M NaOH(aq).    

(b) 13.0 mL of 0.330 M NaOH(aq).
     

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