(1) Calculate moles of acid and base
mol H+ = 0.00529
mol OH- = 0.00759
(2) Calculate excess base
0.00759 - 0.00529 = 0.0023 mol OH-
Calculate the pH of the resulting solution if 23.0 mL of 0.230 M HCl(aq) is added to
(a) 33.0 mL of 0.230 M NaOH(aq).
(b) 13.0 mL of 0.330 M NaOH(aq).
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