The reduction of a metallic oxide is represented by this generic equation:
MxOy(s) + yH2(g) → xM(s) + yH2O(g)
where M represents the symbol for the metal; x and y are the subscripts in the formula.
Calculate ΔH°rxn for the reduction of V2O5. The table is : V2O5(s) = -1550.6 ΔH° kJ/mol : H2(g) = 0 ΔH° kJ/mol : V(s) = 0 ΔH° kJ/mol: H2O(g) -241.82 ΔH° kJ/mol.
Express your answer in 4 significant digits in KJ
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