Balance the redox reaction under acidic conditions:
Cr2+(aq) + H2MoO4(aq) → Cr3+(aq) + Mo(s)
*Before balancing the redox reaction:
• ignore H+, OH-, and H2O in the starting reaction
Step 1: Separate the whole reaction into two half-reactions
Cr2+(aq) → Cr3+(aq) H2MoO4(aq) → Mo(s)
Step 2: Balance the non-hydrogen and non-oxygen elements first
Cr2+(aq) → Cr3+(aq) H2MoO4(aq) → Mo(s)
(Cr: balanced) (Mo: balanced)
Step 3: Balance oxygen by adding H2O(l) to the side that needs oxygen (1 O : 1 H2O)
Cr2+(aq) → Cr3+(aq) H2MoO4(aq) → Mo(s) + 4H2O(l)
(No oxygens)
Balance the following equation in acidic conditions. Phases are optional.
Cr2 + H2MoO4 ::> Cr3 + Mo
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