Problem: Balance the following equation in acidic conditions. Phases are optional. Cr2 + H2MoO4 ::> Cr3  + Mo

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Balance the redox reaction under acidic conditions:


Cr2+(aq)  + H2MoO4(aq) → Cr3+(aq) + Mo(s) 


*Before balancing the redox reaction:

 ignore H+, OH-, and H2O in the starting reaction


Step 1: Separate the whole reaction into two half-reactions


Cr2+(aq)  →  Cr3+(aq)                                                    H2MoO4(aq)Mo(s) 


Step 2: Balance the non-hydrogen and non-oxygen elements first


Cr2+(aq)  →  Cr3+(aq)                                                    H2MoO4(aq)Mo(s) 

(Cr: balanced)                                               (Mo: balanced)


Step 3: Balance oxygen by adding H2O(l) to the side that needs oxygen (1 O : 1 H2O)


Cr2+(aq)  →  Cr3+(aq)                                                    H2MoO4(aq)Mo(s) + 4H2O(l)       

(No oxygens)                                               

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Problem Details

Balance the following equation in acidic conditions. Phases are optional. 

Cr2 + H2MoO4 ::> Cr3  + Mo