Problem: Please answer this question with a brief explanation.The solubility of lead (II) chloride (PbCl2) is 1.6 x 10-2 M. What is the Ksp of PbCl2? A) 4.1 x 10-6 B) 1.6 x 10-5 C) 5.0 X 10-4 D) 3.1 x 10-7 E) 1.6 x 10-2

FREE Expert Solution

Dissociation of PbCl2:


PbCl2(s) ⇌  Pb2+(aq) + 2Cl–(aq)


ICE table. 


The Ksp expression then is:


Ksp=productsreactants=[Pb2+][Cl-]2


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Problem Details

Please answer this question with a brief explanation.

The solubility of lead (II) chloride (PbCl2) is 1.6 x 10-2 M. What is the Ksp of PbCl2? 

A) 4.1 x 10-6 

B) 1.6 x 10-5 

C) 5.0 X 10-4 

D) 3.1 x 10-7 

E) 1.6 x 10-2

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