# Problem: Glucose (a source of energy and metabolic intermediate): 40.00% C, 6.71% H, and 53.29% O.Express your answer as a chemical formula.

###### FREE Expert Solution

Recall that the empirical formula is the simplest whole-number ratio formula of a compound

Step 1: Recall that mass percent is given by:

Assuming we have 100 g of the compound, this means we have 40.0 g C, 6.71 g H, and 53.29 g O.

Now, we need to get the moles of each element in the compound.

The atomic masses are 12.01 g/mol C, 1.01 g/mol H, and 16 g/mol O.

= 3.33 mol C

= 6.64 mol H

= 3.33 mol O

89% (315 ratings) ###### Problem Details

Glucose (a source of energy and metabolic intermediate): 40.00% C, 6.71% H, and 53.29% O.

Express your answer as a chemical formula.

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