Problem: Predict the products for the following precipitation reaction: NiCl2 (aq)+ (NH4)2S(aq) →a) NiS(s) + NH4Cl(aq)b) NiS(aq) + 2NH4Cl(aq)c) NiS(s) + 2NH4Cl(aq)d) NiS(s) + 2NH4Cl(s)

FREE Expert Solution

We will determine the precipitate formed by writing the reaction..

NiCl2(aq) + (NH4)2S(aq)


Reactants:

 NiCl2

▪ chlorine → Group 7A → -1 charge → Cl- 

            Salt is neutral → overall charge = 0

            Overall charge = Ni + Cl- 
            0 = Ni + (-1 x 2)
            0 = Ni + (-2)
            +2 +2
            Ni = +2

▪ nickel → +2 charge → Ni2+

(NH4)2S

▪ ammonium → polyatomic ion → +1 charge → NH4+ 

▪ sulfide → group 6A → -2 charge → S2-

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Problem Details

Predict the products for the following precipitation reaction: 

NiCl2 (aq)+ (NH4)2S(aq) →

a) NiS(s) + NH4Cl(aq)

b) NiS(aq) + 2NH4Cl(aq)

c) NiS(s) + 2NH4Cl(aq)

d) NiS(s) + 2NH4Cl(s)

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