We will determine the precipitate formed by writing the reaction..
NiCl2(aq) + (NH4)2S(aq) →
▪ chlorine → Group 7A → -1 charge → Cl-
Salt is neutral → overall charge = 0
Overall charge = Ni + Cl-
0 = Ni + (-1 x 2)
0 = Ni +
+2 Ni = +2
▪ nickel → +2 charge → Ni2+
▪ ammonium → polyatomic ion → +1 charge → NH4+
▪ sulfide → group 6A → -2 charge → S2-
Predict the products for the following precipitation reaction:
NiCl2 (aq)+ (NH4)2S(aq) →
a) NiS(s) + NH4Cl(aq)
b) NiS(aq) + 2NH4Cl(aq)
c) NiS(s) + 2NH4Cl(aq)
d) NiS(s) + 2NH4Cl(s)
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